If the pictures are not, forced therapy is probably the best option.

This is true, but it really depends how “therapy” is defined. And forced therapy could mean anything from things like the old conversion therapy approach for gay people.

You might argue that these days we wouldn’t do anything so barbaric, but considering that the nature of a pedophile’s is very unsavory, and the fact that it will never be acceptable, unlike homosexuality, people would be far more willing to abuse or exploit said “therapy”

Isn’t this all from one event?

I don’t get why people rush to the next replica platform that will go down the exact same path of overstimulating you / mentally harming you.

Just delete Instagram.

Don’t replace it.

Also 100% clear that facebook, google, twitter… are all doing the same but for US intelligence

Hmm, ok. Let me retry.

The digits of pi are not proven to be uniform or randomly distributed according to any pattern.

Pi could have a point where it stops having 9’s at all.

If that’s the case, it would not contain all sequences that contain the digit 9, and could not contain all sequences.

While we can’t look at all the digits of Pi, we could consider that the uniform behavior of the digits in pi ends at some point, and wherever there would usually be a 9, the digit is instead a 1. This new number candidate for pi is infinite, doesn’t repeat and contains all the known properties of pi.

Therefore, it is possible that not any finite sequence of non-repeating numbers would appear somewhere in Pi.

Prove that said number isn’t pi.

0000000000

It kind of does come across as pedantic – the real question is just that “Does pi contain all sequences”

But because of the way that it is phrased, in mathematics you do a lot of problems/phrasing proofs where you would be expected to follow along exactly in this pedantic manner

OK, fine. Imagine that in pi after the quadrillionth digit, all 1s are replaced with 9. It still holds

The question is

Since pi is infinite and non-repeating, would it mean…

Then the answer is mathematically, no. If X is infinite and non-repeating it doesn’t.

If a number is normal, infinite, and non-repeating, then yes.

To answer the real question “Does any finite sequence of non-repeating numbers appear somewhere in Pi?”

The answer depends on if Pi is normal or not, but not necessarily

Oh yeah, definitely. I mean they definitely ran more than face detection software.

They probably got thousands of tips and chose to respond to the one randomly in Altoona based on other knowledge they had.

It’s crazy to me that parallel construction is allowed.

It’s not really the photos. For me, it’s that it’s really unusual for him to have had all the evidence on hand. Like the ID, gun, silencer, notes, and a motive on hand, just chilling in McDonalds. He also gave away probable cause to search him by presenting the ID which he should have known was fake. Considering he took concealing steps like using a ghost gun, ditching his backpack, and making a relatively clean getaway, it’s pretty odd.

Still it’s obviously possible that he wanted to be caught or was exhausted… or just dumb enough to not think of that.

It IS a big thing that the evidence hasn’t been presented officially yet. There’s a lot of media talk implying that he’s the guy but trial by media is not a verdict